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I need help with math

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User is not online. zackinlego
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27 Jan 2012 05:03 PM
I have a 2x2 square and i want the area of the circle that is inside it but i dont know how


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User is not online. 123yonnd
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27 Jan 2012 05:04 PM
You do know you can't fit a perfect circle in a square, right?


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User is not online. zackinlego
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27 Jan 2012 05:05 PM
yes i do.


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User is not online. 123yonnd
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27 Jan 2012 05:06 PM
So then it's not possible to get a correct answer.


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User is not online. zackinlego
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27 Jan 2012 05:07 PM
it is but it has to be an approximate area.


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User is not online. 123yonnd
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27 Jan 2012 05:07 PM
How small must it be for it to fit?


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User is not online. zackinlego
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27 Jan 2012 05:09 PM
The diameter has to be smaller than half of the square's side


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User is not online. 123yonnd
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27 Jan 2012 05:10 PM
I still don't see how you're getting the area...


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User is not online. zackinlego
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27 Jan 2012 05:11 PM
Well what i meant was the area of the square minus the area of the circle inside it


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User is not online. 123yonnd
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27 Jan 2012 05:13 PM
I'm not sure if I can help without seeing the exact problem you are trying to solve. Maybe if you tell me the purpose of this?


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User is not online. zackinlego
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27 Jan 2012 05:16 PM
its for homework


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User is not online. 123yonnd
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27 Jan 2012 05:20 PM
A) The square is too large to contain a perfect circle. B) Even if you can calculate the area, you won't get an exact answer because there will always be a little bit of the square left out. C) There aren't many uses in finding the approximate area of the circle inside a square.


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User is not online. 123yonnd
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27 Jan 2012 05:23 PM
Although... You could calculate it like this: Square with side length L Radius r = L/2 - (sqrt(5)/4 * L) Area of square A = L^2 Area of circle B = Pi * r^2 The approximate area is: A-B


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User is not online. zackinlego
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27 Jan 2012 05:26 PM
I still dont know how to do it so i just did it with a calculator and got pi r^2


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User is not online. 123yonnd
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27 Jan 2012 05:27 PM
The equation I gave you is the radius of the circle.


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